Hot Chocolatev15
This is documentation for v15, which is currently in preview.
See the latest stable version instead.

Object Types

The most important type in a GraphQL schema is the object type. It contains fields that can return simple scalars like String, Int, or again object types.

SDL
type Author {
name: String
}
type Book {
title: String
author: Author
}

Learn more about object types here.

Definition

Object types can be defined like the following.

In the implementation-first approach we are essentially just creating regular C# classes.

C#
public class Author
{
public string Name { get; set; }
}

Binding behavior

In the implementation-first approach all public properties and methods are implicitly mapped to fields on the schema object type. The same is true for T of ObjectType<T> when using the code-first approach.

In the code-first approach we can also enable explicit binding, where we have to opt-in properties and methods we want to include instead of them being implicitly included.

We can configure our preferred binding behavior globally like the following.

C#
builder.Services
.AddGraphQLServer()
.ModifyOptions(options =>
{
options.DefaultBindingBehavior = BindingBehavior.Explicit;
});
Warning

This changes the binding behavior for all types, not only object types.

We can also override it on a per type basis:

C#
public class BookType : ObjectType<Book>
{
protected override void Configure(IObjectTypeDescriptor<Book> descriptor)
{
descriptor.BindFields(BindingBehavior.Implicit);
// We could also use the following methods respectively
// descriptor.BindFieldsExplicitly();
// descriptor.BindFieldsImplicitly();
}
}

Ignoring fields

In the implementation-first approach we can ignore fields using the [GraphQLIgnore] attribute.

C#
public class Book
{
[GraphQLIgnore]
public string Title { get; set; }
public Author Author { get; set; }
}

Including fields

In the code-first approach we can explicitly include properties of our POCO using the Field method on the IObjectTypeDescriptor. This is only necessary, if the binding behavior of the object type is explicit.

C#
public class BookType : ObjectType<Book>
{
protected override void Configure(IObjectTypeDescriptor<Book> descriptor)
{
descriptor.BindFieldsExplicitly();
descriptor.Field(f => f.Title);
}
}

Naming

Unless specified explicitly, Hot Chocolate automatically infers the names of object types and their fields. Per default the name of the class becomes the name of the object type. When using ObjectType<T> in code-first, the name of T is chosen as the name for the object type. The names of methods and properties on the respective class are chosen as names of the fields of the object type.

The following conventions are applied when transforming C# method and property names into SDL types and fields:

  • Get prefixes are removed: The get operation is implied and therefore redundant information.
  • Async postfixes are removed: The Async is an implementation detail and therefore not relevant to the schema.
  • The first letter is lowercased: This is not part of the specification, but a widely agreed upon standard in the GraphQL world.

If we need to we can override these inferred names.

The [GraphQLName] attribute allows us to specify an explicit name.

C#
[GraphQLName("BookAuthor")]
public class Author
{
[GraphQLName("fullName")]
public string Name { get; set; }
}

This would produce the following BookAuthor schema object type:

SDL
type BookAuthor {
fullName: String
}

If only one of our clients requires specific names, it is better to use aliases in this client's operations than changing the entire schema.

GraphQL
{
MyUser: user {
Username: name
}
}

Explicit types

Hot Chocolate will, most of the time, correctly infer the schema types of our fields. Sometimes we might have to be explicit about it though. For example when we are working with custom scalars or code-first types in general.

In the implementation-first approach we can use the [GraphQLType] attribute.

C#
public class Author
{
[GraphQLType(typeof(StringType))]
public string Name { get; set; }
}

Additional fields

We can add additional (dynamic) fields to our schema types, without adding new properties to our backing class.

C#
public class Author
{
public string Name { get; set; }
public DateTime AdditionalField()
{
// Omitted code for brevity
}
}

What we have just created is a resolver. Hot Chocolate automatically creates resolvers for our properties, but we can also define them ourselves.

Learn more about resolvers

Generics

Note: Read about interfaces and unions before resorting to generic object types.

In the code-first approach we can define generic object types.

C#
public class Response
{
public string Status { get; set; }
public object Payload { get; set; }
}
public class ResponseType<T> : ObjectType<Response>
where T : class, IOutputType
{
protected override void Configure(
IObjectTypeDescriptor<Response> descriptor)
{
descriptor.Field(f => f.Status);
descriptor
.Field(f => f.Payload)
.Type<T>();
}
}
public class Query
{
public Response GetResponse()
{
return new Response
{
Status = "OK",
Payload = 123
};
}
}
public class QueryType : ObjectType<Query>
{
protected override void Configure(IObjectTypeDescriptor<Query> descriptor)
{
descriptor
.Field(f => f.GetResponse())
.Type<ResponseType<IntType>>();
}
}

This will produce the following schema types.

SDL
type Query {
response: Response
}
type Response {
status: String!
payload: Int
}

We have used an object as the generic field above, but we can also make Response generic and add another generic parameter to the ResponseType.

C#
public class Response<T>
{
public string Status { get; set; }
public T Payload { get; set; }
}
public class ResponseType<TSchemaType, TRuntimeType>
: ObjectType<Response<TRuntimeType>>
where TSchemaType : class, IOutputType
{
protected override void Configure(
IObjectTypeDescriptor<Response<TRuntimeType>> descriptor)
{
descriptor.Field(f => f.Status);
descriptor
.Field(f => f.Payload)
.Type<TSchemaType>();
}
}

Naming

If we were to use the above type with two different generic arguments, we would get an error, since both ResponseType have the same name.

We can change the name of our generic object type depending on the used generic type.

C#
public class ResponseType<T> : ObjectType<Response>
where T : class, IOutputType
{
protected override void Configure(
IObjectTypeDescriptor<Response> descriptor)
{
descriptor
.Name(dependency => dependency.Name + "Response")
.DependsOn<T>();
descriptor.Field(f => f.Status);
descriptor
.Field(f => f.Payload)
.Type<T>();
}
}